GE JVM7195SKSS Microwave Dimensions
Published 2026-07-24 ยท Category: microwave
The GE JVM7195SKSS is a 1.9 cu. ft. over-the-range sensor microwave. It is designed to install under a 30-inch-wide cabinet and includes a ventilation fan for use above a standard range or cooktop.
Manufacturer specs list the JVM7195SKSS at 29.875 inches wide, 16.3125 inches tall, and 15.5625 inches deep. With the door open, the required depth is 39.125 inches. The unit weighs 57 lb and runs on a 120V, 15A circuit.
The 29.875-inch width is the standard over-the-range width, meant to align with adjacent 30-inch cabinetry. The 16.3125-inch height is typical for 1.9 cu. ft. models, which are slightly taller than 1.6 or 1.7 cu. ft. units. The 39.125-inch door-open depth matters when the microwave is installed over an island or peninsula where a swinging door may contact a wall or cabinet.
At 57 lb, the JVM7195SKSS is lighter than the 1.6 cu. ft. GE JVM3160RFSS but heavier than the countertop models in the dataset. Its 15A draw is the highest among the cataloged microwaves, so it should be on a dedicated circuit if multiple kitchen appliances share the same outlet. The 1.9 cu. ft. capacity is the largest of the five microwave models currently listed. Its 15.5625-inch depth is typical for over-the-range models that must clear a standard-depth hood.
The table below summarizes the verified dimensions and electrical requirements. For more microwave size context, see the standard microwave sizes guide or the microwave category page.
| Specification | Value |
|---|---|
| Brand | GE Appliances |
| Model | JVM7195SKSS |
| Width | 29.875 in |
| Height | 16.3125 in |
| Depth | 15.5625 in |
| Depth with door open | 39.125 in |
| Capacity | 1.9 cu ft |
| Weight | 57 lb |
| Voltage | 120V |
| Amperage | 15A |
| Source | Manufacturer product page |
All figures come directly from the linked GE Appliances product page.